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: s = 'Hi hi hi bye bye bye word count’ sc.parallelize(seq).map(lambda word: (word, 1)).reduceByKey(add).collect()

Dead Dotterel answered on September 3, 2020 Popularity 1/10 Helpfulness 1/10

answer : s = 'Hi hi hi bye bye bye word count’ sc.parallelize(seq).map(lambda word: (word, 1)).reduceByKey(add).collect()

: s = 'Hi hi hi bye bye bye word count’ sc.parallelize(seq).map(lambda word: (word, 1)).reduceByKey(add).collect()

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from operator import add

s = 'Hi hi hi bye bye bye word count' 
seq = s.split()   # ['Hi', 'hi', 'hi', 'bye', 'bye', 'bye', 'word', 'count']
sc.parallelize(seq)\
  .map(lambda word: (word, 1))\
  .reduceByKey(add)\
  .collect()

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Source: pythonpedia.com

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Contributed on Sep 03 2020

Dead Dotterel

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: s = 'Hi hi hi bye bye bye word count’ sc.parallelize(seq).map(lambda word: (word, 1)).reduceByKey(add).collect()

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