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get distinct values from array of arrays

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Outrageous Oyster answered on April 3, 2020 Popularity 9/10 Helpfulness 4/10

answer get distinct values from array of arrays

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get distinct values from array of arrays

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const arrOfObjs = [
    {
      name: 'someName',
      tags: [
        'sci-fi',
        'strategy',
        'sandbox',
      ]
    },
    {
      name: 'someOtherName',
      tags: [ 
        'sci-fi', 
        'mining', 
        'woodcutting', 
        'sandbox'
      ]
    }
  ];

let uniqueTags = [...new Set(arrOfObj.map(obj => obj.tags).flat(1))];

// ['sci-fi', 'strategy', 'sandbox', 'mining', 'woodcutting']

Popularity 9/10 Helpfulness 4/10 Language javascript

Source: Grepper

Tags: arrays distinct-values get javascript

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Contributed on Nov 12 2022

Outrageous Oyster

0 Answers Avg Quality 2/10

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js get distinct values from array

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var myArray = ['a', 1, 'a', 2, '1'];

let unique = [...new Set(myArray)];

console.log(unique); // unique is ['a', 1, 2, '1']

Popularity 10/10 Helpfulness 7/10 Language javascript

Source: stackoverflow.com

Tags: distinct-values

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Contributed on Aug 09 2021

Jeff

0 Answers Avg Quality 2/10

javascript get distinct values from array

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const categories = ['General', 'Exotic', 'Extreme', 'Extreme', 'General' ,'Water', 'Extreme']
.filter((value, index, categoryArray) => categoryArray.indexOf(value) === index);

This will return an array that has the unique category names
['General', 'Exotic', 'Extreme', 'Water']

Popularity 10/10 Helpfulness 6/10 Language javascript

Source: Grepper

Tags: distinct-values

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Contributed on Apr 03 2020

McBurd

0 Answers Avg Quality 2/10

Distinct Elements in Array

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#include <iostream>
#include <vector>
#include <unordered_set>

using namespace std;

int main() {
    int n, m;
    cin >> n >> m;
    
    vector<int> array(n);
    for (int i = 0; i < n; i++) {
        cin >> array[i];
    }
    
    unordered_set<int> distinctNumbers;
    vector<int> count(n + 1, 0);
    
    for (int i = n - 1; i >= 0; i--) {
        distinctNumbers.insert(array[i]);
        count[i + 1] = distinctNumbers.size();
    }
    
    for (int i = 0; i < m; i++) {
        int li;
        cin >> li;
        
        if (li > n) {
            cout << 0 << endl;
        } else {
            cout << count[li] << endl;
        }
    }
    
    return 0;
}

Popularity 8/10 Helpfulness 1/10 Language typescript

Source: chat.openai.com

Tags: distinct distinc

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Contributed on Jul 05 2023

202_Harsh Verma

0 Answers Avg Quality 2/10

get distinct values from array of arrays

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