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spread js

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Anton Grigoriev answered on August 19, 2022 Popularity 10/10 Helpfulness 2/10

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const user = { name: 'user', password: 'user'}
const admin = { name 'admin', rights: 'root'}

let merge = Object.assign({}, user, admin) 
console.log(merge) 
// {name 'admin', password: 'user', rights: 'root'}

merge = {...user, ...admin} // spread operator
console.log(merge)
// {name 'admin', password: 'user', rights: 'root'}

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript spread

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Contributed on Aug 19 2022

Anton Grigoriev

0 Answers Avg Quality 2/10

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//ES6 spread operator, equivalent to .concat() method: array1.concat(array2)
let arr1 = ['1', '2', '3'] //using let because the reference is gonna change.
const arr2 = [4, 5, 6] //const because the reference for arrr2 is not gonna change
arr1 = [...arr1, ...arr2]  //the triple dots ... removes the [ and ] leaving only an "instance of" inside.

output:
['1', '2', '3', 4, 5, 6 ]

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: concat co

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Contributed on Oct 29 2022

Rodrigo E Toobe

0 Answers Avg Quality 2/10

spread js

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const array = [1, 2, 3];
const obj = { ...array }; // { 0: 1, 1: 2, 2: 3 }

Popularity 8/10 Helpfulness 1/10 Language javascript

Source: developer.mozilla.org

Tags: javascript spread spr

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Contributed on Jul 23 2023

Cute Capybara

0 Answers Avg Quality 2/10

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