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Number.prototype.between = function(a, b) { var min = Math.min.apply(Math, [a, b]), max = Math.max.apply(Math, [a, b]); return this > min && this < max; };

Fancy Fly answered on December 22, 2020 Popularity 5/10 Helpfulness 2/10

answer Number.prototype.between = function(a, b) { var min = Math.min.apply(Math, [a, b]), max = Math.max.apply(Math, [a, b]); return this > min && this < max; };

Number.prototype.between = function(a, b) { var min = Math.min.apply(Math, [a, b]), max = Math.max.apply(Math, [a, b]); return this > min && this < max; };

Comment

x = findMax(1, 123, 500, 115, 44, 88);

function findMax() {
  var i;
  var max = -Infinity;
  for (i = 0; i < arguments.length; i++) {
    if (arguments[i] > max) {
      max = arguments[i];
    }
  }
  return max;
}

Popularity 5/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript max min return this var

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Contributed on Dec 22 2020

Fancy Fly

0 Answers Avg Quality 2/10

Closely Related Answers

Number.prototype.between = function(a, b) { var min = Math.min.apply(Math, [a, b]), max = Math.max.apply(Math, [a, b]); return this > min && this < max; };

Comment

//get min/max value of arrays
function getArrayMax(array){
   return Math.max.apply(null, array);
}
function getArrayMin(array){
   return Math.min.apply(null, array);
}
var ages=[11, 54, 32, 92];
var maxAge=getArrayMax(ages); //92
var minAge=getArrayMin(ages); //11

Popularity 4/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript max this var return min

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Contributed on Dec 22 2020

Fancy Fly

0 Answers Avg Quality 2/10

Number.prototype.between = function(a, b) { var min = Math.min.apply(Math, [a, b]), max = Math.max.apply(Math, [a, b]); return this > min && this < max; };

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More Related Answers

Number.prototype.between = function(a, b) { var min = Math.min.apply(Math, [a, b]), max = Math.max.apply(Math, [a, b]); return this > min && this < max; };

Closely Related Answers

Number.prototype.between = function(a, b) { var min = Math.min.apply(Math, [a, b]), max = Math.max.apply(Math, [a, b]); return this > min && this < max; };

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