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Cheerful Chamois answered on April 6, 2020 Popularity 10/10 Helpfulness 4/10

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js group by

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const groupBy = (arr, prop) =>
  arr.reduce((acc, val) => {
    ;(acc[val[prop]] = acc[val[prop]] || []).push(val)
    return acc
  }, {})

Popularity 10/10 Helpfulness 4/10 Language javascript

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Tags: group-by javascript

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Contributed on Sep 18 2022

Cheerful Chamois

0 Answers Avg Quality 2/10

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javascript array group by

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function groupByKey(array, key) {
   return array
     .reduce((hash, obj) => {
       if(obj[key] === undefined) return hash; 
       return Object.assign(hash, { [obj[key]]:( hash[obj[key]] || [] ).concat(obj)})
     }, {})
}


var cars = [{'make':'audi','model':'r8','year':'2012'},{'make':'audi','model':'rs5','year':'2013'},{'make':'ford','model':'mustang','year':'2012'},{'make':'ford','model':'fusion','year':'2015'},{'make':'kia','model':'optima','year':'2012'}];

var result = groupByKey(cars, 'make');

JSON.stringify(result,"","\t");
{
	"audi": [
		{
			"make": "audi",
			"model": "r8",
			"year": "2012"
		},
		{
			"make": "audi",
			"model": "rs5",
			"year": "2013"
		}
	],
	"ford": [
		{
			"make": "ford",
			"model": "mustang",
			"year": "2012"
		},
		{
			"make": "ford",
			"model": "fusion",
			"year": "2015"
		}
	],
	"kia": [
		{
			"make": "kia",
			"model": "optima",
			"year": "2012"
		}
	]
}

Popularity 10/10 Helpfulness 6/10 Language javascript

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Tags: group-by group-b

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Contributed on Sep 15 2020

Vijaysinh Parmar

0 Answers Avg Quality 2/10

javascript array group by id

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var results = orgs.reduce(function(results, org) {
    (results[org.id] = results[org.id] || []).push(org);
    return results;
}, {})

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: stackoverflow.com

Tags: group-by group-b

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Contributed on Apr 06 2020

Bewildered Bird

0 Answers Avg Quality 2/10

group by in javascript

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let group = cars.reduce((r, a) => { console.log("a", a); console.log('r', r); r[a.make] = [...r[a.make] || [], a]; return r;}, {});console.log("group", group);

Popularity 10/10 Helpfulness 3/10 Language javascript

Source: medium.com

Tags: group-by group-b

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Contributed on May 06 2020

Bhishma'S

0 Answers Avg Quality 2/10

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