Breaking News: Grepper is joining You.com. Read the official announcement!

.NET JSON: DeserializeAsync

Add Answer

Arti answered on November 25, 2022 Popularity 9/10 Helpfulness 5/10

answer .NET JSON: DeserializeAsync

related .NET JSON: Deserialize

related c# deserialize json

related deserialize json c#

.NET JSON: DeserializeAsync

Comment

using System.Text.Json;

namespace DeserializeFromFileAsync
{
    public class WeatherForecast
    {
        public DateTimeOffset Date { get; set; }
        public int TemperatureCelsius { get; set; }
        public string? Summary { get; set; }
    }

    public class Program
    {
        public static async Task Main()
        {
            string fileName = "WeatherForecast.json";
            using FileStream openStream = File.OpenRead(fileName);
            WeatherForecast? weatherForecast = 
                await JsonSerializer.DeserializeAsync<WeatherForecast>(openStream);

            Console.WriteLine($"Date: {weatherForecast?.Date}");
            Console.WriteLine($"TemperatureCelsius: {weatherForecast?.TemperatureCelsius}");
            Console.WriteLine($"Summary: {weatherForecast?.Summary}");
        }
    }
}
// output:
//Date: 8/1/2019 12:00:00 AM -07:00
//TemperatureCelsius: 25
//Summary: Hot

Popularity 9/10 Helpfulness 5/10 Language csharp

Source: learn.microsoft.com

Tags: .net c#

Link to this answer
Share Copy Link

Contributed on Nov 25 2022

Arti

0 Answers Avg Quality 2/10

Closely Related Answers

.NET JSON: Deserialize

Comment

using System.Text.Json;

namespace DeserializeFromFile
{
    public class WeatherForecast
    {
        public DateTimeOffset Date { get; set; }
        public int TemperatureCelsius { get; set; }
        public string? Summary { get; set; }
    }

    public class Program
    {
        public static void Main()
        {
            string fileName = "WeatherForecast.json";
            string jsonString = File.ReadAllText(fileName);
            WeatherForecast weatherForecast = JsonSerializer.Deserialize<WeatherForecast>(jsonString)!;

            Console.WriteLine($"Date: {weatherForecast.Date}");
            Console.WriteLine($"TemperatureCelsius: {weatherForecast.TemperatureCelsius}");
            Console.WriteLine($"Summary: {weatherForecast.Summary}");
        }
    }
}
// output:
//Date: 8/1/2019 12:00:00 AM -07:00
//TemperatureCelsius: 25
//Summary: Hot

Popularity 10/10 Helpfulness 5/10 Language csharp

Source: learn.microsoft.com

Tags: .net

Link to this answer
Share Copy Link

Contributed on Nov 25 2022

Arti

0 Answers Avg Quality 2/10

c# deserialize json

Comment

//format(object array): [{},{},{}]
List<Employee> emps = Newtonsoft.Json.JsonConvert.DeserializeObject<List<Employee>>(jsonString);
//format(object): {}
Employee emp = Newtonsoft.Json.JsonConvert.DeserializeObject<Employee>(jsonString);

Popularity 10/10 Helpfulness 4/10 Language csharp

Source: Grepper

Tags: c# c

Link to this answer
Share Copy Link

Contributed on Dec 10 2022

AB_498

0 Answers Avg Quality 2/10

deserialize json c#

Comment

using System;
using System.Text.Json;

public class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public class Program
{
    public static void Main()
    {
        string json = "{\"Name\":\"John\",\"Age\":30}";

        // Deserialize JSON to object
        Person person = JsonSerializer.Deserialize<Person>(json);

        Console.WriteLine("Name: " + person.Name);
        Console.WriteLine("Age: " + person.Age);
    }
}

Popularity 9/10 Helpfulness 4/10 Language csharp

Source: Grepper

Link to this answer
Share Copy Link

Contributed on Sep 11 2023

YOU.com

0 Answers Avg Quality 2/10

.NET JSON: DeserializeAsync

Contents

More Related Answers

.NET JSON: DeserializeAsync

Closely Related Answers

.NET JSON: Deserialize

c# deserialize json

deserialize json c#

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.