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Promise.all

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The little dog answered on February 26, 2020 Popularity 10/10 Helpfulness 4/10

answer Promise.all

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Promise.all

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const promise1 = Promise.resolve(3);
const promise2 = 42;
const promise3 = new Promise(function(resolve, reject) {
  setTimeout(resolve, 100, 'foo');
});

Promise.all([promise1, promise2, promise3]).then(function(values) {
  console.log(values);
});
// expected output: Array [3, 42, "foo"]

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: developer.mozilla.org

Tags: javascript promise.all

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Contributed on Mar 23 2020

The little dog

0 Answers Avg Quality 2/10

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javascript promise all

Comment

var p1 = Promise.resolve(3);
var p2 = 1337;
var p3 = new Promise((resolve, reject) => {
  setTimeout(resolve, 100, "foo");
}); 

Promise.all([p1, p2, p3]).then(values => { 
  console.log(values); // [3, 1337, "foo"] 
});

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: developer.mozilla.org

Tags: javascript j

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Contributed on Feb 26 2020

Tense Tarantula

0 Answers Avg Quality 2/10

javascript promise.all

Comment

  try {
    const [res1, res2, res3] = await Promise.all([
      Promise1,
      Promise2,
      Promise3,
    ]);
  } catch (err) {
    console.error(err);
  }

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Feb 21 2021

Cherry berry

0 Answers Avg Quality 2/10

javascript promise all

Comment

var p1 = new Promise((resolve, reject) => { 
  setTimeout(resolve, 1000, "one"); 
}); 
var p2 = new Promise((resolve, reject) => { 
  setTimeout(resolve, 2000, "two"); 
});
var p3 = new Promise((resolve, reject) => {
  setTimeout(resolve, 3000, "three");
});
var p4 = new Promise((resolve, reject) => {
  setTimeout(resolve, 4000, "four");
});
var p5 = new Promise((resolve, reject) => {
  reject("reject");
});

Promise.all([p1, p2, p3, p4, p5]).then(values => { 
  console.log(values);
}, reason => {
  console.log(reason)
});

//From console:
//"reject"

// Evenly, it's possible to use .catch
Promise.all([p1, p2, p3, p4, p5]).then(values => { 
  console.log(values);
}).catch(reason => { 
  console.log(reason)
});

//From console: 
//"reject"

Popularity 10/10 Helpfulness 3/10 Language javascript

Source: developer.mozilla.org

Tags: javascript j

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Contributed on Feb 26 2020

Tense Tarantula

0 Answers Avg Quality 2/10

javascript promise.all

Comment

// PARALLEL PROMISES
async function fetchMoviesAndCategories() {
  const [moviesResponse, categoriesResponse] = await Promise.all([
    fetch('/movies'),
    fetch('/categories')
  ]);

  const movies = await moviesResponse.json();
  const categories = await categoriesResponse.json();

  return [movies, categories];
}

Popularity 10/10 Helpfulness 3/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Feb 21 2021

Cherry berry

0 Answers Avg Quality 2/10

promise.all in javascript

Comment

const video1 = new Promise((resolve, reject) => {
  resolve("video1 loaded");
});
const video2 = new Promise((resolve, reject) => {
  resolve("Video2 loaded");
});
const video3 = new Promise((resolve, reject) => {
  resolve("video3 loaded");
});

Promise.all([video1, video2, video3]).then((messages) => {
  console.log("messages", messages);
});

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: keep.google.com

Tags: javascript j

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Contributed on Oct 10 2022

Kalyan

0 Answers Avg Quality 2/10

javascript Promise.all()

Comment

var p1 = Promise.resolve(3);
var p2 = 1337;
var p3 = new Promise((resolve, reject) => {
  setTimeout(resolve, 100, "foo");
});

Promise.all([p1, p2, p3]).then(values => {
  console.log(values); // [3, 1337, "foo"]
});

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: developer.mozilla.org

Tags: javascript j

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Contributed on Jan 11 2022

Jolly Jackal

0 Answers Avg Quality 2/10

how to use promise.all

Comment

const contentPromise = requestUser();
 const commentsPromise = requestComments();

 const combinedContent = Promise.all([contentPromise, commentsPromise])
   .then(([content, comments]) => {
     // content and comments have both finished loading.
   })

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: stackoverflow.com

Tags: javascript j

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Contributed on Oct 28 2021

Nice Narwhal

0 Answers Avg Quality 2/10

promise all in promise all

Comment

var arr = [
  {subarr: [1,2,3]},
  {subarr: [4,5,6]},
  {subarr: [7,8,9]}
];
function processAsync(n) {
  return new Promise(function(resolve) {
    setTimeout(
      function() { resolve(n * n); },
      Math.random() * 1e3
    );
  });
}
Promise.all(arr.map(function(entity){
  return Promise.all(entity.subarr.map(function(item){
    return processAsync(item);
  }));
})).then(function(data) {
  console.log(data);
});

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: stackoverflow.com

Tags: javascript j

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Contributed on Nov 06 2020

Better Barracuda

0 Answers Avg Quality 2/10

promise.all

Comment

var p1 = Promise.resolve(3);
var p2 = 1337;
var p3 = new Promise((resolve, reject) => {
  setTimeout(() => {
    resolve("foo");
  }, 100);
});

Promise.all([p1, p2, p3]).then(values => {
  console.log(values); // [3, 1337, "foo"]
});

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: developer.mozilla.org

Tags: javascript j

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Contributed on Jun 15 2021

Grieving Goat

0 Answers Avg Quality 2/10

Promise.all

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