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comparing two array of objects in javascript returning differences

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Naughty Nightingale answered on July 8, 2020 Popularity 10/10 Helpfulness 4/10

answer comparing two array of objects in javascript returning differences

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comparing two array of objects in javascript returning differences

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a = [{ value:"4a55eff3-1e0d-4a81-9105-3ddd7521d642", display:"Jamsheer"}, { value:"644838b3-604d-4899-8b78-09e4799f586f", display:"Muhammed"}, { value:"b6ee537a-375c-45bd-b9d4-4dd84a75041d", display:"Ravi"}, { value:"e97339e1-939d-47ab-974c-1b68c9cfb536", display:"Ajmal"},  { value:"a63a6f77-c637-454e-abf2-dfb9b543af6c", display:"Ryan"}]
b = [{ value:"4a55eff3-1e0d-4a81-9105-3ddd7521d642", display:"Jamsheer", $$hashKey:"008"}, { value:"644838b3-604d-4899-8b78-09e4799f586f", display:"Muhammed", $$hashKey:"009"}, { value:"b6ee537a-375c-45bd-b9d4-4dd84a75041d", display:"Ravi", $$hashKey:"00A"}, { value:"e97339e1-939d-47ab-974c-1b68c9cfb536", display:"Ajmal", $$hashKey:"00B"}]

function comparer(otherArray){
  return function(current){
    return otherArray.filter(function(other){
      return other.value == current.value && other.display == current.display
    }).length == 0;
  }
}

var onlyInA = a.filter(comparer(b));
var onlyInB = b.filter(comparer(a));

result = onlyInA.concat(onlyInB);

console.log(result);

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: stackoverflow.com

Tags: javascript

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Contributed on Jul 08 2020

Naughty Nightingale

0 Answers Avg Quality 2/10

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javascript compare two arrays of objects get same elements

Comment

var result = result1.filter(function (o1) {
    return result2.some(function (o2) {
        return o1.id === o2.id; // return the ones with equal id
   });
});
// if you want to be more clever...
let result = result1.filter(o1 => result2.some(o2 => o1.id === o2.id));

Popularity 10/10 Helpfulness 8/10 Language javascript

Source: stackoverflow.com

Tags: arrays ar

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Contributed on Aug 03 2020

CsuBison

0 Answers Avg Quality 2/10

javascript compare two arrays of objects

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//Find values that are in result1 but not in result2
var uniqueResultOne = result1.filter(function(obj) {
    return !result2.some(function(obj2) {
        return obj.value == obj2.value;
    });
});

//Find values that are in result2 but not in result1
var uniqueResultTwo = result2.filter(function(obj) {
    return !result1.some(function(obj2) {
        return obj.value == obj2.value;
    });
});

//Combine the two arrays of unique entries
var result = uniqueResultOne.concat(uniqueResultTwo);

Popularity 10/10 Helpfulness 3/10 Language javascript

Source: stackoverflow.com

Tags: arrays ar

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Contributed on Apr 04 2022

Hurt Hamster

0 Answers Avg Quality 2/10

javascript compare two arrays of objects return difference

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const arr1 = [{id:1}];
const arr2 = [{user: {id:1}}];

const arr3 = arr1.filter(({ _id: id1 }) => !arr2.some(({ user: { id: id2 } }) => id2 === id1));

Popularity 1/10 Helpfulness 1/10 Language javascript

Source: Grepper

Tags: arrays compare difference javascript return

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Contributed on Feb 04 2022

Mysterious Manx

0 Answers Avg Quality 2/10

comparing two array of objects in javascript returning differences

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