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xhr post send

Splendid Shrew answered on July 15, 2020 Popularity 10/10 Helpfulness 6/10

answer xhr post send

xhr post send

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var xhr = new XMLHttpRequest();
var params = 'field1='+postfield1+'&field2='+postfield2;
xhr.open('POST', 'http://exmaple.com', true);

//Send the proper header information along with the request
xhr.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');

xhr.onload = function() {//Call a function when the state changes.
    if(xhr.status == 200) {
        alert(this.responseText);
    }
}
xhr.send(params);

Popularity 10/10 Helpfulness 6/10 Language javascript

Source: stackoverflow.com

Tags: javascript post send

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