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convert python code to pseudocode online

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Attractive Addax answered on May 11, 2022 Popularity 9/10 Helpfulness 2/10

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from flask import render_template, request, Flask
import joblib

app = Flask(__name__)

model = joblib.load('dicisionTreeModel.pkl')


@app.route('/')
def index():
    return render_template('Main.html')


@app.route('/predict', methods=['GET','POST'])
def predict():
    if (request.method) =='POST':
        age = request.form.get('age')
        sysBloodPress = request.form.get('sysBloodPress')
        diaBloodPress = request.form.get('diaBloodPress')
        bloodGlucoseLevel = request.form.get('bloodGlucoseLevel')
        bodyTemp = request.form.get('bodyTemp')
        heartRate = request.form.get('heartRate')
        data = [age, sysBloodPress, diaBloodPress,
                bloodGlucoseLevel, bodyTemp, heartRate]
        patientPredict = model.predict([data])[0]
        if patientPredict < 1.5:
            return render_template('Main.html', predict=f'Your Risk Level is {patientPredict}, which is Low')
        elif patientPredict < 2.5:
            return render_template('Main.html', predict=f'Your Risk Level is {patientPredict}, which is Medium')
        else:
            return render_template('Main.html', predict=f'Your Risk Level is {patientPredict}, which is High')


if __name__ == "__main__":
    app.run(debug=True)

Popularity 9/10 Helpfulness 2/10 Language python

Source: www.pwnict.co.uk

Tags: pseudocode python

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Contributed on May 11 2022

Attractive Addax

0 Answers Avg Quality 2/10

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convert python code to pseudocode online

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def is_balanced(line):
    '''Determine if all parentheses in an entered line of code form matching pairs.
    Note: Pairs of parentheses may be nested.'''
    stack = []
    for char in line:
        if char == '(':
            stack.append(char)
        elif char == ')':
            if len(stack) == 0:
                return False
            stack.pop()
    return len(stack) == 0

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Source: Grepper

Tags: pseudocode python pyth

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Contributed on May 16 2022

Mokshagna samineni 21BAI10363

0 Answers Avg Quality 2/10

convert python code to pseudocode online

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//Group 5 ECE-3A
#include <Servo.h> //include libraries needed
#include <DS3231.h>
#include <LiquidCrystal.h>
#include <Keypad.h> 

const byte ROWS = 4; //set the 4x4 keypad keys
const byte COLS = 4;

char keys[ROWS][COLS] = { //assign in array the corresponding numbers and symbols in  keypad
  {'7','8','9','/'},
  {'4','5','6','x'},
  {'1','2','3','-'},
  {'c','0','=','+'}
};
byte rowPins[ROWS] = { 2, 3, 4, 5 };
byte colPins[COLS] = { 6, 7, 8, 9 };

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Source: Grepper

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Contributed on Jun 15 2022

Kathy Capulong Dela Cruz

0 Answers Avg Quality 2/10

online python pseudo code writer python

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if(i>10/)
print('lll')

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Source: Grepper

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Contributed on Aug 07 2022

HamidReza Ghaedsharaf

0 Answers Avg Quality 2/10

convert python code to pseudocode online

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ef admin():
    print("\n Admin Log in ")
    with open("admin.txt", "r") as file:
        file_reader = csv.reader(file)
        user_find(file_reader)
        file.close()


def user_find(file):
    user = input("Username: ")
    for row in file:
        if row[0] == user:
            user_found = [row[0], row[1]]
            pass_check(user_found)
            break
        else:
            print("\nInvalid entry, try again.")
            admin()


def pass_check(user_found):
    user = input("Password: ")
    while user_found[1] == user:
        print(adminfunc())
    for user_found[1] in user:
        if user_found[1] != user:
            print("\nInvalid entry, try again.")
            admin()

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Source: Grepper

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Contributed on Aug 21 2022

Anas Hassabou

0 Answers Avg Quality 2/10

python to pseudo code converter

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ef admin():
    print("\n Admin Log in ")
    with open("admin.txt", "r") as file:
        file_reader = csv.reader(file)
        user_find(file_reader)
        file.close()


def user_find(file):
    user = input("Username: ")
    for row in file:
        if row[0] == user:
            user_found = [row[0], row[1]]
            pass_check(user_found)
            break
        else:
            print("\nInvalid entry, try again.")
            admin()


def pass_check(user_found):
    user = input("Password: ")
    while user_found[1] == user:
        print(adminfunc())
    for user_found[1] in user:
        if user_found[1] != user:
            print("\nInvalid entry, try again.")
            admin()

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Source: Grepper

Tags: converter python

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Contributed on Aug 21 2022

Anas Hassabou

0 Answers Avg Quality 2/10

python to pseudo code converter online

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years=int(input("enter the value of years "))
if (y%400==0) or (y%4==0 and y%100!=0):
  print('(0) is a leap year'.format(years))
else:
  print('(0) is not a leap year'.format(years))

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Contributed on Sep 21 2022

reem Alamri

0 Answers Avg Quality 2/10

python to pseudo code converter online

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a = int(input("Enter a year: "))
if a % 400 == 0:
    LeapYear = True
elif a % 100 == 0:
    LeapYear = False
elif a % 4 == 0:
    LeapYear = True
else:
    LeapYear = False

if LeapYear:
    print(a, " Is a leap year")
else:
    print(a, " Is not a leap year")

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Contributed on Oct 01 2022

Mariam R

0 Answers Avg Quality 2/10

convert python code to pseudocode online

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def denoise_sequence(sequence,iterations):
    # Sample noise
    img = torch.tensor(sequence,device=device).float()
    if len(img.size())==2:
        img=img.unsqueeze(1)
    else:
        img=img.unsqueeze(0).unsqueeze(0)
    with torch.no_grad():
        for i in range(0,int(iterations))[::-1]:
            t = torch.full((1,), i, device=device)
            img = denoise_timestep(img, t)
    return img

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Source: Grepper

Tags: pseudocode python

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Contributed on Nov 04 2022

Marçal Bravo Padrós

0 Answers Avg Quality 2/10

pseudo code generator online python

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#Ask the user for their name
print("Welcome to Maths Quest")
name=input("What is your name? ")

num= input(name + " Which Times Table Would you like to Practice? (1-12) ")

#Ask The Number To generate Table

print("OK " + name + ": on a piece of paper, write down the " + num + " times table from 1 to 12. When you’re ready I’ll show you the answer so you can check your work." )

while True:
    print("Are you ready? Enter 'y' to start " )
    y = input()
    y = y.upper()
    if y == "Y":
        break
    
while True:
    for times in range (1, 13):
        print(int(num), ' x ', times , ' = ' , int(num)*times)
    break
print("Did you get them all correct? Enter 'Y' for yes or 'N' for no: ")
y = input()
y = y.upper()
if y == 'Y':
    print("Great Job! Thank you for playing the Maths Quest.")
  
else:
    print("Try Again.....Better Luck Next Time ")

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Tags: generator python

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Contributed on Nov 08 2022

Shonal Dutt

0 Answers Avg Quality 2/10

convert python code to pseudocode online

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