Breaking News: Grepper is joining You.com. Read the official announcement!

dice roller python

Add Answer

An7wan answered on September 7, 2020 Popularity 8/10 Helpfulness 5/10

answer dice roller python

related dice simulator in python

related simulate dice roll python

related Dice Roller in Python

related how to make a dice program in python

related roll dice python

related how to make dice roll in python

related roll dice python

dice roller python

Comment

#dice roller ascii art
import random

input("Welcome to Ascii Dice roller\n")

dice_6 = " _____ \n|X X X|\n|     |\n|X X X|\n ----- \n   "
dice_4 = " _____ \n|X   X|\n|     |\n|X   X|\n ----- \n   "
dice_5 = " _____ \n|X   X|\n|  X  |\n|X   X|\n ----- \n   "
dice_1 = " _____ \n|     |\n|  X  |\n|     |\n ----- \n   "
dice_2 = " _____ \n|   X |\n|     |\n| X   |\n ----- \n   "
dice_3 = " _____ \n|   X |\n|  X  |\n| X   |\n ----- \n   "

Dice = [dice_1,dice_2,dice_3,dice_4,dice_5,dice_6]

# makes greet cool
rolls = random.choice(Dice)
print(rolls)

# whle loop from dice roller
while True:
    try:
        person_input = int(input("How many dice would you like to roll?...{1-5}\n"))
        if(person_input > 0 and person_input < 6):
            break
        else:
        print("Too Many\n")
    except:
        print("Woah Woah type a number")

#define rolls and formating the output
def dice_rolls(dice_amount):

    for dice in range(dice_amount):
        rolls =random.choice(Dice)
        print(rolls)
#      prints^the # of rolls
dice_rolls(person_input)

Popularity 8/10 Helpfulness 5/10 Language python

Source: Grepper

Tags: dice python

Link to this answer
Share Copy Link

Contributed on Oct 08 2022

An7wan

0 Answers Avg Quality 2/10

Closely Related Answers

dice simulator in python

Comment

import speech_recognition as sr
import pyttsx3
import random

engine = pyttsx3.init('sapi5')
voices = engine.getProperty('voices')
# print(voices[1].id)
engine.setProperty('voice', voices[0].id)


def speak(audio):
    engine.say(audio)
    engine.runAndWait()

no = random.randint(1,6)
print(no)

if no == 1:
        print("[-----]")
        print("[     ]")
        print("[  0  ]")
        print("[     ]")
        print("[-----]")
if no == 2:
        print("[-----]")
        print("[ 0   ]")
        print("[     ]")
        print("[   0 ]")
        print("[-----]")
if no == 3:
        print("[-----]")
        print("[     ]")
        print("[0 0 0]")
        print("[     ]")
        print("[-----]")
if no == 4:
        print("[-----]")
        print("[0   0]")
        print("[     ]")
        print("[0   0]")
        print("[-----]")
if no == 5:
        print("[-----]")
        print("[0   0]")
        print("[  0  ]")
        print("[0   0]")
        print("[-----]")
if no == 6:
        print("[-----]")
        print("[0 0 0]")
        print("[     ]")
        print("[0 0 0]")
        print("[-----]")
          
speak(f"your number is: {no}")

Popularity 9/10 Helpfulness 8/10 Language python

Source: Grepper

Tags: python py

Link to this answer
Share Copy Link

Contributed on Jan 12 2022

Coding boy Hasya

0 Answers Avg Quality 2/10

simulate dice roll python

Comment

# high depends on what type of dice you are playing with
# size depends on how many dice you want to play with
# If you consider playing with 10 coins as dices, then high = 2 (1 coin has 2 sides) and no_of_dice = 10
# If you consider playing with 5 ludo dices, then high = 6 (1 dice has 6 sides) and no_of_dice = 5
# replace=True for any previous occurrence is likely to occur again
import numpy as np
simulation = np.random.choice(list(range(1,high+1)), size=no_of_dice, replace=True)

Popularity 6/10 Helpfulness 6/10 Language javascript

Source: Grepper

Tags: dice javascript python pyt

Link to this answer
Share Copy Link

Contributed on Jan 08 2023

Innocent Iguana

0 Answers Avg Quality 2/10

Dice Roller in Python

Comment

#importing module for random number generation
import random

#range of the values of a dice
min_val = 1
max_val = 6

#to loop the rolling through user input
roll_again = "yes"

#loop
while roll_again == "yes" or roll_again == "y":
    print("Rolling The Dices...")
    print("The Values are :")
    
    #generating and printing 1st random integer from 1 to 6
    print(random.randint(min_val, max_val))
    
    #generating and printing 2nd random integer from 1 to 6
    print(random.randint(min_val, max_val))
    
    #asking user to roll the dice again. Any input other than yes or y will terminate the loop
    roll_again = input("Roll the Dices Again?")

Popularity 9/10 Helpfulness 5/10 Language python

Source: gist.githubusercontent.com

Tags: dice python

Link to this answer
Share Copy Link

Contributed on Nov 16 2021

Terrible Toucan

0 Answers Avg Quality 2/10

how to make a dice program in python

Comment

import random
run = 1
level = 0
while(run == 1):
        print("**ROUND " + str(level) + "**") 
        print("player 1: ",random.randint(0, 6))
        print("player 2: ",random.randint(0, 6))
        run = int(input("enter 1 to go again or 0 to end: "))
        print("")
        level += 1

Popularity 9/10 Helpfulness 4/10 Language python

Source: Grepper

Tags: dice python pyth

Link to this answer
Share Copy Link

Contributed on Sep 07 2020

TheRubberDucky

0 Answers Avg Quality 2/10

roll dice python

Comment

import random
import time
def diceroll():
    D=input("roll the dice?(y/n):")
    a=True
    while a:
        if D=='y':
            b=random.randint(1,6)
            print("rolling dice....")
            time.sleep(1)
            print("you got",b)
            time.sleep(0.55)
            c=input("roll again?:")
        if D=='n':
            a=False
            break
diceroll()

Popularity 1/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: dice python

Link to this answer
Share Copy Link

Contributed on Aug 27 2022

hip hop tech

0 Answers Avg Quality 2/10

how to make dice roll in python

Comment

-1

#OM NAMAH SHIVA


import random
#computer picks a random number between 1 to 6
computer_choice = random.randint(1, 6)

print("you have 5 try's you scores more wins")
user_choice = int(input(["choose a number between 1 to 6"]))

#users_choice should not be higher than 6 
if user_choice >= 7:
    input("it should be between 1 to 6")
    #if user_choice input higher number than 7 two times it will quit the game
    if user_choice >= 7:
        exit()
#if user_choice is equal to computer_choice you win
if user_choice == computer_choice:
    print("you win")
    exit()

#if user_choice not equal to computer_choice you lose
else:
    print("you lose")

Popularity 6/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: dice python

Link to this answer
Share Copy Link

Contributed on Nov 05 2022

Jai Deip Reddy

0 Answers Avg Quality 2/10

roll dice python

Comment

import random

roll_dice = random.randint(1, 6)
print(roll_dice)

Popularity 1/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: dice python

Link to this answer
Share Copy Link

Contributed on Jan 26 2021

Frail Frog

0 Answers Avg Quality 2/10

dice roller python

Contents

More Related Answers

dice roller python

Closely Related Answers

dice simulator in python

simulate dice roll python

Dice Roller in Python

how to make a dice program in python

roll dice python

how to make dice roll in python

roll dice python

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.