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import re #your code goes here number=input() pattern=r"(1|8|9)[0-9]+" match=re.match(pattern,number) of lane(number)==8: if(match): print("value") else: print("invalid") else print("invalid")

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Open Opossum answered on February 5, 2022 Popularity 1/10 Helpfulness 1/10

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  • answer import re #your code goes here number=input() pattern=r"(1|8|9)[0-9]+" match=re.match(pattern,number) of lane(number)==8: if(match): print("value") else: print("invalid") else print("invalid")

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  • import re handle = open('regex_sum_330187.txt') for line in handle : line = line.rstrip() numbers = re.findall('([0-9]+)',line) print(sum(numbers))

    • import re #your code goes here number=input() pattern=r"(1|8|9)[0-9]+" match=re.match(pattern,number) of lane(number)==8: if(match): print("value") else: print("invalid") else print("invalid")

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    Popularity 1/10 Helpfulness 1/10 Language python
    Source: Grepper
    Tags: import python
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    Open Opossum
    Contributed on Feb 05 2022
    Open Opossum
    0 Answers  Avg Quality 2/10

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