Breaking News: Grepper is joining You.com. Read the official announcement!

python smtp email

Add Answer

Silly Scarab answered on March 20, 2022 Popularity 10/10 Helpfulness 5/10

answer python smtp email

related python SMTP sendmail

related python script send email smtp

related python send smtp email

related python send mail without smtplib

python smtp email

Comment

from email.message import EmailMessage
import smtplib
import os
import random
from dotenv import load_dotenv
from quote import quote

load_dotenv(".env")

SENDER = os.environ.get("GMAIL_USER")
PASSWORD = os.environ.get("GMAIL_PASSWORD")

def send_email(recipient, subject, body):
    msg = EmailMessage()
    msg.set_content(body)
    msg["Subject"] = subject
    msg["From"] = SENDER
    msg["To"] = recipient
    server = smtplib.SMTP_SSL("smtp.gmail.com", 465)
    server.login(SENDER, PASSWORD)
    server.send_message(msg)
    server.quit()

quotes = quote("William Shakespeare", limit=50)
body = random.sample(quotes, k=1)[0]['quote']

send_email("replace_me@hey.com", subject="Quote of the Day", body=body)

Popularity 10/10 Helpfulness 5/10 Language python

Source: dev.to

Tags: email python smtp

Link to this answer
Share Copy Link

Contributed on Mar 20 2022

Silly Scarab

0 Answers Avg Quality 2/10

Closely Related Answers

python SMTP sendmail

Comment

-1

#!/usr/bin/env python

import smtplib
from email.mime.text import MIMEText

sender = 'admin@example.com'
receivers = ['info@example.com']


port = 1025
msg = MIMEText('This is test mail')

msg['Subject'] = 'Test mail'
msg['From'] = 'admin@example.com'
msg['To'] = 'info@example.com'

with smtplib.SMTP('localhost', port) as server:
    
    # server.login('username', 'password')
    server.sendmail(sender, receivers, msg.as_string())
    print("Successfully sent email")

Popularity 10/10 Helpfulness 5/10 Language python

Source: zetcode.com

Tags: python py

Link to this answer
Share Copy Link

Contributed on Mar 24 2022

Active Programmer

0 Answers Avg Quality 2/10

python script send email smtp

Comment

import smtplib
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart

def send_email():
    # Email details
    sender_email = 'your_email@example.com'
    receiver_email = 'recipient@example.com'
    subject = 'Test Email'
    body = 'This is a test email sent using Python script and SMTP.'

    # Create the email message
    message = MIMEMultipart()
    message['From'] = sender_email
    message['To'] = receiver_email
    message['Subject'] = subject

    # Attach the body to the email
    message.attach(MIMEText(body, 'plain'))

    try:
        # Setup SMTP server and send the email
        smtp_server = 'smtp.example.com'
        smtp_port = 587
        smtp_username = 'your_smtp_username'
        smtp_password = 'your_smtp_password'

        with smtplib.SMTP(smtp_server, smtp_port) as server:
            server.starttls()
            server.login(smtp_username, smtp_password)
            server.send_message(message)
        print("Email sent successfully!")
    except Exception as e:
        print("Something went wrong while sending the email:", str(e))

# Call the function to send the email
send_email()

Popularity 7/10 Helpfulness 4/10 Language python

Source: Grepper

Link to this answer
Share Copy Link

Contributed on Sep 12 2023

YOU.com

0 Answers Avg Quality 2/10

python send smtp email

Comment

import smtplib
from email.mime.text import MIMEText

smtp_server = 'your_smtp_server'
smtp_port = 587
sender_email = 'sender@example.com'
receiver_email = 'receiver@example.com'
password = 'your_password'

message = MIMEText('This is the content of the email.')

message['Subject'] = 'Example Subject'
message['From'] = sender_email
message['To'] = receiver_email

try:
    with smtplib.SMTP(smtp_server, smtp_port) as server:
        server.starttls()
        server.login(sender_email, password)
        server.send_message(message)
    print('Email sent successfully!')
except Exception as e:
    print('An error occurred while sending the email:', str(e))

Popularity 7/10 Helpfulness 3/10 Language python

Source: Grepper

Link to this answer
Share Copy Link

Contributed on Sep 11 2023

YOU.com

0 Answers Avg Quality 2/10

python send mail without smtplib

Comment

import httplib2
import os
import oauth2client
from oauth2client import client, tools, file
import base64
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from apiclient import errors, discovery
import mimetypes
from email.mime.image import MIMEImage
from email.mime.audio import MIMEAudio
from email.mime.base import MIMEBase

SCOPES = 'https://www.googleapis.com/auth/gmail.send'
CLIENT_SECRET_FILE = 'client_secret.json'
APPLICATION_NAME = 'Gmail API Python Send Email'

def get_credentials():
    home_dir = os.path.expanduser('~')
    credential_dir = os.path.join(home_dir, '.credentials')
    if not os.path.exists(credential_dir):
        os.makedirs(credential_dir)
    credential_path = os.path.join(credential_dir,
                                   'gmail-python-email-send.json')
    store = oauth2client.file.Storage(credential_path)
    credentials = store.get()
    if not credentials or credentials.invalid:
        flow = client.flow_from_clientsecrets(CLIENT_SECRET_FILE, SCOPES)
        flow.user_agent = APPLICATION_NAME
        credentials = tools.run_flow(flow, store)
        print('Storing credentials to ' + credential_path)
    return credentials

def SendMessage(sender, to, subject, msgHtml, msgPlain, attachmentFile=None):
    credentials = get_credentials()
    http = credentials.authorize(httplib2.Http())
    service = discovery.build('gmail', 'v1', http=http)
    if attachmentFile:
        message1 = createMessageWithAttachment(sender, to, subject, msgHtml, msgPlain, attachmentFile)
    else: 
        message1 = CreateMessageHtml(sender, to, subject, msgHtml, msgPlain)
    result = SendMessageInternal(service, "me", message1)
    return result

def SendMessageInternal(service, user_id, message):
    try:
        message = (service.users().messages().send(userId=user_id, body=message).execute())
        print('Message Id: %s' % message['id'])
        return message
    except errors.HttpError as error:
        print('An error occurred: %s' % error)
        return "Error"
    return "OK"

def CreateMessageHtml(sender, to, subject, msgHtml, msgPlain):
    msg = MIMEMultipart('alternative')
    msg['Subject'] = subject
    msg['From'] = sender
    msg['To'] = to
    msg.attach(MIMEText(msgPlain, 'plain'))
    msg.attach(MIMEText(msgHtml, 'html'))
    return {'raw': base64.urlsafe_b64encode(msg.as_bytes())}

def createMessageWithAttachment(
    sender, to, subject, msgHtml, msgPlain, attachmentFile):
    """Create a message for an email.

    Args:
      sender: Email address of the sender.
      to: Email address of the receiver.
      subject: The subject of the email message.
      msgHtml: Html message to be sent
      msgPlain: Alternative plain text message for older email clients          
      attachmentFile: The path to the file to be attached.

    Returns:
      An object containing a base64url encoded email object.
    """
    message = MIMEMultipart('mixed')
    message['to'] = to
    message['from'] = sender
    message['subject'] = subject

    messageA = MIMEMultipart('alternative')
    messageR = MIMEMultipart('related')

    messageR.attach(MIMEText(msgHtml, 'html'))
    messageA.attach(MIMEText(msgPlain, 'plain'))
    messageA.attach(messageR)

    message.attach(messageA)

    print("create_message_with_attachment: file: %s" % attachmentFile)
    content_type, encoding = mimetypes.guess_type(attachmentFile)

    if content_type is None or encoding is not None:
        content_type = 'application/octet-stream'
    main_type, sub_type = content_type.split('/', 1)
    if main_type == 'text':
        fp = open(attachmentFile, 'rb')
        msg = MIMEText(fp.read(), _subtype=sub_type)
        fp.close()
    elif main_type == 'image':
        fp = open(attachmentFile, 'rb')
        msg = MIMEImage(fp.read(), _subtype=sub_type)
        fp.close()
    elif main_type == 'audio':
        fp = open(attachmentFile, 'rb')
        msg = MIMEAudio(fp.read(), _subtype=sub_type)
        fp.close()
    else:
        fp = open(attachmentFile, 'rb')
        msg = MIMEBase(main_type, sub_type)
        msg.set_payload(fp.read())
        fp.close()
    filename = os.path.basename(attachmentFile)
    msg.add_header('Content-Disposition', 'attachment', filename=filename)
    message.attach(msg)

    return {'raw': base64.urlsafe_b64encode(message.as_string())}


def main():
    to = "to@address.com"
    sender = "from@address.com"
    subject = "subject"
    msgHtml = "Hi<br/>Html Email"
    msgPlain = "Hi\nPlain Email"
    SendMessage(sender, to, subject, msgHtml, msgPlain)
    # Send message with attachment: 
    SendMessage(sender, to, subject, msgHtml, msgPlain, '/path/to/file.pdf')

if __name__ == '__main__':
    main()

Popularity 9/10 Helpfulness 2/10 Language python

Source: stackoverflow.com

Tags: python py

Link to this answer
Share Copy Link

Contributed on Nov 04 2022

Careful Caracal

0 Answers Avg Quality 2/10

python smtp email

Contents

More Related Answers

python smtp email

Closely Related Answers

python SMTP sendmail

python script send email smtp

python send smtp email

python send mail without smtplib

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.