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python sort dict by sub value

Jittery Jaguar answered on May 21, 2022 Popularity 3/10 Helpfulness 5/10

answer python sort dict by sub value

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python sort dict by sub value

Comment

# Python3 code to demonstrate
# Sort nested dictionary by key
# using sorted()
  
# initializing dictionary
test_dict = {'Nikhil' : { 'roll' : 24, 'marks' : 17},
             'Akshat' : {'roll' : 54, 'marks' : 12}, 
             'Akash' : { 'roll' : 12, 'marks' : 15}}
  
# printing original dict
print("The original dictionary : " + str(test_dict))
  
# using sorted()
# Sort nested dictionary by key
res = sorted(test_dict.items(), key = lambda x: x[1]['marks'])
  
# print result
print("The sorted dictionary by marks is : " + str(res))

Popularity 3/10 Helpfulness 5/10 Language python

Source: www.geeksforgeeks.org

Tags: python

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Contributed on May 21 2022

Jittery Jaguar

0 Answers Avg Quality 2/10

Closely Related Answers

python sort dict by sub value

Comment

# Python3 code to demonstrate
# Sort nested dictionary by key
# using sorted()
  
# initializing dictionary
test_dict = {'Nikhil' : { 'roll' : 24, 'marks' : 17},
             'Akshat' : {'roll' : 54, 'marks' : 12}, 
             'Akash' : { 'roll' : 12, 'marks' : 15}}
  
# printing original dict
print("The original dictionary : " + str(test_dict))
  
# using sorted()
# Sort nested dictionary by key
res = sorted(test_dict.items(), key = lambda x: x[1]['marks'])
  
# print result
print("The sorted dictionary by marks is : " + str(res))

Popularity 1/10 Helpfulness 3/10 Language python

Source: www.geeksforgeeks.org

Tags: python

Link to this answer
Share Copy Link

Contributed on May 21 2022

Jittery Jaguar

0 Answers Avg Quality 2/10

python sort dict by sub value

Comment

# Python3 code to demonstrate
# Sort nested dictionary by key
# using sorted()
  
# initializing dictionary
test_dict = {'Nikhil' : { 'roll' : 24, 'marks' : 17},
             'Akshat' : {'roll' : 54, 'marks' : 12}, 
             'Akash' : { 'roll' : 12, 'marks' : 15}}
  
# printing original dict
print("The original dictionary : " + str(test_dict))
  
# using sorted()
# Sort nested dictionary by key
res = sorted(test_dict.items(), key = lambda x: x[1]['marks'])
  
# print result
print("The sorted dictionary by marks is : " + str(res))

Popularity 1/10 Helpfulness 1/10 Language python

Source: www.geeksforgeeks.org

Tags: python

Link to this answer
Share Copy Link

Contributed on May 21 2022

Jittery Jaguar

0 Answers Avg Quality 2/10

python sort dict by sub value

Comment

# Python3 code to demonstrate
# Sort nested dictionary by key
# using sorted()
  
# initializing dictionary
test_dict = {'Nikhil' : { 'roll' : 24, 'marks' : 17},
             'Akshat' : {'roll' : 54, 'marks' : 12}, 
             'Akash' : { 'roll' : 12, 'marks' : 15}}
  
# printing original dict
print("The original dictionary : " + str(test_dict))
  
# using sorted()
# Sort nested dictionary by key
res = sorted(test_dict.items(), key = lambda x: x[1]['marks'])
  
# print result
print("The sorted dictionary by marks is : " + str(res))

Popularity 1/10 Helpfulness 1/10 Language python

Source: www.geeksforgeeks.org

Tags: python

Link to this answer
Share Copy Link

Contributed on May 21 2022

Jittery Jaguar

0 Answers Avg Quality 2/10

python sort dict by sub value

Comment

# Python3 code to demonstrate
# Sort nested dictionary by key
# using sorted()
  
# initializing dictionary
test_dict = {'Nikhil' : { 'roll' : 24, 'marks' : 17},
             'Akshat' : {'roll' : 54, 'marks' : 12}, 
             'Akash' : { 'roll' : 12, 'marks' : 15}}
  
# printing original dict
print("The original dictionary : " + str(test_dict))
  
# using sorted()
# Sort nested dictionary by key
res = sorted(test_dict.items(), key = lambda x: x[1]['marks'])
  
# print result
print("The sorted dictionary by marks is : " + str(res))

Popularity 1/10 Helpfulness 1/10 Language python

Source: www.geeksforgeeks.org

Tags: python

Link to this answer
Share Copy Link

Contributed on May 21 2022

Jittery Jaguar

0 Answers Avg Quality 2/10

python sort dict by sub value

Comment

# Python3 code to demonstrate
# Sort nested dictionary by key
# using sorted()
  
# initializing dictionary
test_dict = {'Nikhil' : { 'roll' : 24, 'marks' : 17},
             'Akshat' : {'roll' : 54, 'marks' : 12}, 
             'Akash' : { 'roll' : 12, 'marks' : 15}}
  
# printing original dict
print("The original dictionary : " + str(test_dict))
  
# using sorted()
# Sort nested dictionary by key
res = sorted(test_dict.items(), key = lambda x: x[1]['marks'])
  
# print result
print("The sorted dictionary by marks is : " + str(res))

Popularity 3/10 Helpfulness 1/10 Language python

Source: www.geeksforgeeks.org

Tags: python

Link to this answer
Share Copy Link

Contributed on May 21 2022

Jittery Jaguar

0 Answers Avg Quality 2/10

python sort dict by sub value

Comment

# Python3 code to demonstrate
# Sort nested dictionary by key
# using sorted()
  
# initializing dictionary
test_dict = {'Nikhil' : { 'roll' : 24, 'marks' : 17},
             'Akshat' : {'roll' : 54, 'marks' : 12}, 
             'Akash' : { 'roll' : 12, 'marks' : 15}}
  
# printing original dict
print("The original dictionary : " + str(test_dict))
  
# using sorted()
# Sort nested dictionary by key
res = sorted(test_dict.items(), key = lambda x: x[1]['marks'])
  
# print result
print("The sorted dictionary by marks is : " + str(res))

Popularity 1/10 Helpfulness 1/10 Language python

Source: www.geeksforgeeks.org

Tags: python

Link to this answer
Share Copy Link

Contributed on May 21 2022

Jittery Jaguar

0 Answers Avg Quality 2/10

python sort dict by sub value

Comment

# Python3 code to demonstrate
# Sort nested dictionary by key
# using sorted()
  
# initializing dictionary
test_dict = {'Nikhil' : { 'roll' : 24, 'marks' : 17},
             'Akshat' : {'roll' : 54, 'marks' : 12}, 
             'Akash' : { 'roll' : 12, 'marks' : 15}}
  
# printing original dict
print("The original dictionary : " + str(test_dict))
  
# using sorted()
# Sort nested dictionary by key
res = sorted(test_dict.items(), key = lambda x: x[1]['marks'])
  
# print result
print("The sorted dictionary by marks is : " + str(res))

Popularity 1/10 Helpfulness 1/10 Language python

Source: www.geeksforgeeks.org

Tags: python

Link to this answer
Share Copy Link

Contributed on May 21 2022

Jittery Jaguar

0 Answers Avg Quality 2/10

python sort dict by sub value

Comment

# Python3 code to demonstrate
# Sort nested dictionary by key
# using sorted()
  
# initializing dictionary
test_dict = {'Nikhil' : { 'roll' : 24, 'marks' : 17},
             'Akshat' : {'roll' : 54, 'marks' : 12}, 
             'Akash' : { 'roll' : 12, 'marks' : 15}}
  
# printing original dict
print("The original dictionary : " + str(test_dict))
  
# using sorted()
# Sort nested dictionary by key
res = sorted(test_dict.items(), key = lambda x: x[1]['marks'])
  
# print result
print("The sorted dictionary by marks is : " + str(res))

Popularity 1/10 Helpfulness 1/10 Language python

Source: www.geeksforgeeks.org

Tags: python

Link to this answer
Share Copy Link

Contributed on May 21 2022

Jittery Jaguar

0 Answers Avg Quality 2/10

python sort dict by sub value

Comment

# Python3 code to demonstrate
# Sort nested dictionary by key
# using sorted()
  
# initializing dictionary
test_dict = {'Nikhil' : { 'roll' : 24, 'marks' : 17},
             'Akshat' : {'roll' : 54, 'marks' : 12}, 
             'Akash' : { 'roll' : 12, 'marks' : 15}}
  
# printing original dict
print("The original dictionary : " + str(test_dict))
  
# using sorted()
# Sort nested dictionary by key
res = sorted(test_dict.items(), key = lambda x: x[1]['marks'])
  
# print result
print("The sorted dictionary by marks is : " + str(res))

Popularity 1/10 Helpfulness 1/10 Language python

Source: www.geeksforgeeks.org

Tags: python

Link to this answer
Share Copy Link

Contributed on May 21 2022

Jittery Jaguar

0 Answers Avg Quality 2/10

python sort dict by sub value

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python sort dict by sub value

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python sort dict by sub value

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python sort dict by sub value

python sort dict by sub value

python sort dict by sub value

python sort dict by sub value

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