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dict sort

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Colorful Cowfish answered on May 23, 2020 Popularity 10/10 Helpfulness 2/10

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-2

[(k,di[k]) for k in sorted(di.keys())]

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Contributed on Aug 21 2020

Colorful Cowfish

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dictionary sort python

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d={
  3: 4,
  1: 1,
  0: 0,
  4: 3,
  2: 1
}
y=dict(sorted(d.items(), key=lambda item: item[1]))
print(y) # {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

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Contributed on Jul 17 2022

Impossible Ibis

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sort dictionary python

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l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = dict(sorted(l.items(),key=lambda x:x[1],reverse=True))
print(d1) #output : {2: 60, 3: 50, 1: 40, 4: 30, 5: 20}
d2 = dict(sorted(l.items(),key=lambda x:x[1],reverse=False))
print(d2) #output : {5: 20, 4: 30, 1: 40, 3: 50, 2: 60}

Popularity 10/10 Helpfulness 8/10 Language python

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Contributed on Sep 10 2021

Rajanit Navapara

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sort dictionary

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#for dictionary d
sorted(d.items(), key=lambda x: x[1]) #for inceasing order
sorted(d.items(), key=lambda x: x[1], reverse=True) # for decreasing order
#it will return list of key value pair tuples

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Contributed on May 23 2020

Annoying Anteater

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python dict sortieren

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# dict has no order - use a list to store
l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = list(sorted(l.items(),key=lambda x:x[1],reverse=True))

Popularity 9/10 Helpfulness 4/10 Language python

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Contributed on May 22 2022

Marc Tolkmitt

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python dictionary sort

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# empty dictionary
dictionary = {}
# lists
list_1 = [1, 2, 3, 4, 5]
list_2 = ["e", "d", "c", "b", "a"]
# populate a dictionary.
for key, value in zip(list_1, list_2):
    dictionary[key] = value
# original
print(f"Original dictionary: {dictionary}")

# Sort dictionary based on value
dictionary_sorted = dict(sorted(dictionary.items(), key=lambda value: value[1]))
print(f"Sort dictionary by value: {dictionary_sorted}")

# Sort dictionary based on key
dictionary_sorted = dict(sorted(dictionary.items(), key=lambda key: key[0]))
print(f"Sort dictionary by key: {dictionary_sorted}")

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Contributed on May 23 2022

S_Fryer

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sort a dictionary

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d={1:'Monday',2:'Tuesday',3:'Wednesday',\
   4:'Thursday',5:'Friday',6:'Satuday',7:'Sunday'}
d_sort=dict(sorted(d.items(), key=lambda x:x[0],reverse=True))

print(d_sort)

{7: 'Sunday', 6: 'Satuday', 5: 'Friday', 4: 'Thursday', 3: 'Wednesday', 2: 'Tuesday', 1: 'Monday'}

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Contributed on Feb 22 2022

aniket thakur

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dict sort

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