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sed with variable

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DreamCoder answered on November 23, 2021 Popularity 6/10 Helpfulness 1/10

answer sed with variable

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sed with variable

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Using double quotes
Use double quotes to make the shell expand variables while preserving whitespace:

sed -i "s/$var1/ZZ/g" "$file"
When you require the quote character in the replacement string, you have to precede it with a backslash which will be interpreted by the shell. In the following example, the string quote me will be replaced by "quote me" (the character & is interpreted by sed):

sed -i "s/quote me/\"&\"/" "$file"
Using single quotes
If you've a lot shell meta-characters, consider using single quotes for the pattern, and double quotes for the variable:

sed -i 's,'"$pattern"',Say hurrah to &: \0/,' "$file"

Popularity 6/10 Helpfulness 1/10 Language shell

Source: askubuntu.com

Tags: sed shell

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Contributed on Aug 21 2023

DreamCoder

0 Answers Avg Quality 2/10

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bash sed with variable

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# If you want to store your regex in a bash variable 
# and use it in sed, you might need the following
BASE_REGEX="[0-9]{4}\.[0-9]+"
REGEX_ESCAPED=$(sed 's/[}{)(+]/\\&/g; s/\^/\\^/g' <<< "$BASE_REGEX")

# One variable can be used with sed
sed -i "s/${REGEX_ESCAPED}/REPLACEMENT/g" file.txt
# The other can be used with bash internal regex operator
if [[ "2022.42" =~ ^${BASE_REGEX}$ ]]
then
	echo 'Matches !'
fi

Popularity 9/10 Helpfulness 4/10 Language shell

Source: Grepper

Tags: bash

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Contributed on Nov 23 2021

Shy Shrew

0 Answers Avg Quality 2/10

sed variables

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with variables .. use " " 
# replace in line 80 to 83 -> AC(dimer) with CT 
start_line=80
end_line=83
replacement="CT"
sed -i -e  "${start_line},${end_line} s/${dimer[j]}/${replacement}/g" frcmod.beta.${dimer[j]}  # if you remove /g replace only first instant of the line
										^another var 	              ^file

Popularity 5/10 Helpfulness 1/10 Language shell

Source: Grepper

Tags: sed variables whatever

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Contributed on Apr 10 2023

Niransha

0 Answers Avg Quality 2/10

sed with variable

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