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bash xargs with command substitution

Charles-Alexandre Roy answered on August 10, 2022 Popularity 4/10 Helpfulness 8/10

answer bash xargs with command substitution

bash xargs with command substitution

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# Basic syntax:
command_1 | xargs -I {} sh -c "command_2 \$(command_3 {})"
# Where:
#	- -I specifies a string that will be replaced by the stdin when found.
#		This is useful for controlling where the piped content appears in the
#		xargs command
#	- sh -c runs the shell command in quotes which can be used to do command
#		substitution in xargs
#	- the command inside $() is run first and its output is used by command_2

# Example usage:
echo "word1 word2" | xargs -I {} sh -c "echo \$(echo {} | tr a-z A-Z)"

Popularity 4/10 Helpfulness 8/10 Language shell

Source: stackoverflow.com

Tags: bash command-substitution shell xargs

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