“#include<stdio.h> int main() { int n; scanf("%d",&n); int ar[n]; int count=0; for(int i=0;i<n;i++) { scanf("%d",&ar[i]); } for(int i=0;i<n;i++) { for(int j=0;j<n;j++) { if(ar[i]==ar[j]) { count=count+1; } else { count=0; } } } printf("%d\n",(count)/2); }” Code Answer


#include int main() { int n; scanf("%d",&n); int ar[n]; int count=0; for(int i=0;i
whatever by Agreeable Ant on May 07 2020 Donate
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Whatever answers related to “#include<stdio.h> int main() { int n; scanf("%d",&n); int ar[n]; int count=0; for(int i=0;i<n;i++) { scanf("%d",&ar[i]); } for(int i=0;i<n;i++) { for(int j=0;j<n;j++) { if(ar[i]==ar[j]) { count=count+1; } else { count=0; } } } printf("%d\n",(count)/2); }”


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