“int main(){ int t; cin>>t; (t--){ int n, m; cin>>n>>m; vector<vector<int>> M(n, vector<int>(m, 0)); for(int i = 0;i < n;i++){ for(int j = 0;j < m;j++) cin>>M[i][j]; } Solution ob; cout<<ob.maxGold(n, m, M)<<"\n"; } return 0;” Code Answer


int main(){ int t; cin>>t; (t--){ int n, m; cin>>n>>m; vector> M(n, vector(m, 0)); for(int i = 0;i < n;i++){ for(int j = 0;j < m;j++) cin>>M[i][j]; } Solution ob; cout<
whatever by Magnificent Mink on Jul 20 2021 Comment
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