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answer s=0 def sum(x,y): n=int(input("enter no. of terms") for i in range(n): l=int(input("enter no.")) s=s+l print(s) sum()

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i=int(input("enter the number")); sum=0; pro=1; while(i>0): d=1%10; if (d%2==0): sum=sum+d; else: pro=pro*d; i=i//10; print("sum=",sum,"product=",pro);

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#include <iostream> using namespace std; int main(){ int sum1 = 100+50; int sum2 = sum1+250; int sum3 = sum2+sum2; cout<< sum1 << "\n"; cout<< sum2 << "\n"; cout<< sum3 << "\n"; return 0; }

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suma = 0 for i in range(10): suma = suma + i print(suma)

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1. Sum of integers between ‘a’ and ‘b’#

. You have written a function to add two numbers: int Add(int a, int b) { return a+b; } The above function takes two numbers as input and returns their sum.

. You have written a function to add two numbers: int Add(int a, int b) { return a+b; } The above function takes two numbers as input and returns their sum.

Problem Statement For an integer n, let S(n) be the sum of digits in the decimal notation of n. For example, we have S(123) = 1 + 2 + 3 = 6 Given two 3-digit integers A and B, find the greater of S(A) and S(B). Constraints • All values in input are inte