Breaking News: Grepper is joining You.com. Read the official announcement!

leetcode word break

YOU.com answered on September 12, 2023 Popularity 8/10 Helpfulness 2/10

answer leetcode word break

leetcode word break

Comment

def word_break(s, word_dict):
    n = len(s)
    dp = [False] * (n+1)
    dp[0] = True

    for i in range(1, n+1):
        for j in range(i):
            if dp[j] and (s[j:i] in word_dict):
                dp[i] = True
                break

    return dp[n]

Popularity 8/10 Helpfulness 2/10 Language python

Source: Grepper

Link to this answer
Share Copy Link

Contributed on Sep 12 2023

YOU.com

0 Answers Avg Quality 2/10

Continue with Google

By continuing, I agree that I have read and agree to Greppers's Terms of Service and Privacy Policy.

leetcode word break

Contents

More Related Answers

leetcode word break

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.