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word pattern python

abdullah answered on July 17, 2021 Popularity 6/10 Helpfulness 6/10

answer word pattern python

related word pattern in python

word pattern python

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import string

def word_to_pattern(word):
    # Stores actual-letter to pattern-placeholder mapping
    mapping = {}

    # ZYXW... so we cap pop letters starting with A from the end
    available_pattern_letters = list(string.ascii_uppercase)[::-1]

    pattern = []
    for letter in word.upper():
        if letter not in string.ascii_uppercase:
            # for punctuation etc
            pattern.append(letter)
            continue
        if letter not in mapping:
            # new letter we haven't seen yet in this word
            mapping[letter] = available_pattern_letters.pop()
        pattern.append(mapping[letter])
    return pattern.join("")

Popularity 6/10 Helpfulness 6/10 Language python

Source: stackoverflow.com

Tags: python word

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Contributed on Jul 17 2021

abdullah

0 Answers Avg Quality 2/10

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word pattern in python

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def wordPattern(pattern, s):
    dict1 = {}
    dict2 = {}

    for key,value in enumerate(list(s.split(" "))):
        if value not in dict1:
            dict1[value]= [key]
        else:
            dict1[value].append(key)

    for key,value in enumerate(pattern):
        if value not in dict2:
            dict2[value]= [key]
        else:
            dict2[value].append(key)

    return (list(dict1.values()) == list(dict2.values()))

Popularity 4/10 Helpfulness 7/10 Language python

Source: eolnuha.com

Tags: python word

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Contributed on Jul 05 2022

Eol Nuha

0 Answers Avg Quality 2/10

word pattern python

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word pattern python

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word pattern in python

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