Breaking News: Grepper is joining You.com. Read the official announcement!

image_file = models.ImageField(upload_to='images') image_url = models.URLField()

Crowded Constrictor answered on August 24, 2021 Popularity 6/10 Helpfulness 3/10

answer image_file = models.ImageField(upload_to='images') image_url = models.URLField()

image_file = models.ImageField(upload_to='images') image_url = models.URLField()

Comment

from django.db import models
from django.core.files import File
from urllib.request import urlopen
from tempfile import NamedTemporaryFile

class Item(models.Model):
    image_file = models.ImageField(upload_to='images')
    image_url = models.URLField()

    def save(self, *args, **kwargs):
        if self.image_url and not self.image_file:
            img_temp = NamedTemporaryFile(delete=True)
            img_temp.write(urlopen(self.image_url).read())
            img_temp.flush()
            self.image_file.save(f"image_{self.pk}", File(img_temp))
        super(Item, self).save(*args, **kwargs)

Popularity 6/10 Helpfulness 3/10 Language python

Source: stackoverflow.com

Tags: python

Link to this answer
Share Copy Link

Contributed on Aug 24 2021

Crowded Constrictor

0 Answers Avg Quality 2/10

image_file = models.ImageField(upload_to='images') image_url = models.URLField()

Contents

More Related Answers

image_file = models.ImageField(upload_to='images') image_url = models.URLField()

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.