pronic number program in python

Mighty Unicorn answered on December 10, 2021 Popularity 5/10 Helpfulness 4/10

answer pronic number program in python

pronic number program in python

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n = int(input("Enter a number: "))
f = 0
for i in range(n):
    if i * (i + 1) == n:
        f = 1
        break

if f==1:
    print("Pronic number")
else:
    print("Not a Pronic number")

Popularity 5/10 Helpfulness 4/10 Language python

Source: www.codespeedy.com

Tags: python

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Contributed on Dec 10 2021

Mighty Unicorn

0 Answers Avg Quality 2/10

pronic number program in python

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