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sort by the n-th field of each tuple

PythonPower answered on August 26, 2022 Popularity 1/10 Helpfulness 1/10

answer sort by the n-th field of each tuple

sort by the n-th field of each tuple

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def sortby(somelist, n):
    nlist = [(x[n], x) for x in somelist]
    nlist.sort()
    return [val for (key, val) in nlist]
  
def sortby_inplace(somelist, n):
  somelist[:] = [(x[n], x) for x in somelist]
  somelist.sort()
  somelist[:] = [val for (key, val) in somelist]
  return
  
>>> somelist = [(1, 2, 'def'), (2, -4, 'ghi'), (3, 6, 'abc')]
>>> somelist.sort()
>>> somelist
[(1, 2, 'def'), (2, -4, 'ghi'), (3, 6, 'abc')]
>>> nlist = sortby(somelist, 2)
>>> sortby_inplace(somelist, 2)
>>> nlist == somelist
True
>>> nlist = sortby(somelist, 1)
>>> sortby_inplace(somelist, 1)
>>> nlist == somelist
True

Popularity 1/10 Helpfulness 1/10 Language python

Source: wiki.python.org

Tags: each field python

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Contributed on Aug 26 2022

PythonPower

0 Answers Avg Quality 2/10

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sort by the n-th field of each tuple

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