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PHP ajaxDATA2

Obnoxious Ostrich answered on October 31, 2022 Popularity 1/10 Helpfulness 1/10

answer PHP ajaxDATA2

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PHP ajaxDATA2

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<?
if(isset($_GET['country'])){
    $html = '<select name="B" class="input_text" id="B">';
    include 'config/config.php'; 
    $dpttitle = mysql_real_escape_string($_GET['country']);
    $sql="SELECT * FROM department WHERE DeptCode=$dpttitle";
    $result=mysql_query($sql);$options="";
    while ($row=mysql_fetch_array($result)){    
    $did=$row["DeptCode"];
    $depts=$row["Dept"];
    $html .="<OPTION value='$did'>".$depts;}?>
    $html .= '<option value="0">Select...</option>';
    $html .= '</option>';
    $html .= '</select>';
    echo $html;
}
?>

Popularity 1/10 Helpfulness 1/10 Language php

Source: stackoverflow.com

Tags: php

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Contributed on Oct 31 2022

Obnoxious Ostrich

0 Answers Avg Quality 2/10

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$("#A").change(loadCities);
function loadCities(e){
    // prepare get statement
    var url = "http://www.yoursite.com/ajax/getCities";
    var data = {
        country : $("#A").val()
    };
    $.get(url, data, loadCitiesComplete);
}
function loadCitiesComplete(data){
    $("#B").html(data);
}

Popularity 2/10 Helpfulness 1/10 Language php

Source: stackoverflow.com

Tags: php

Link to this answer
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Contributed on Oct 31 2022

Obnoxious Ostrich

0 Answers Avg Quality 2/10

PHP ajaxDATA2

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