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pyton fileter

Salo Hopeless answered on February 9, 2023 Popularity 3/10 Helpfulness 7/10

answer pyton fileter

pyton fileter

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# returns True if the argument passed is even

def check_even(number):
    if number % 2 == 0:
          return True  

    return False


numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

# if an element passed to check_even() returns True, select it
even_numbers_iterator = filter(check_even, numbers)

# converting to list
even_numbers = list(even_numbers_iterator)

print(even_numbers)

# Output: [2, 4, 6, 8, 10]

Popularity 3/10 Helpfulness 7/10 Language python

Source: Grepper

Tags: python

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Contributed on Feb 09 2023

Salo Hopeless

0 Answers Avg Quality 2/10

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