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Implementing LogBrowserFilter

Pragya Keshap answered on February 21, 2023 Popularity 1/10 Helpfulness 1/10

answer Implementing LogBrowserFilter

Implementing LogBrowserFilter

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import org.apache.logging.log4j.LogManager;
import org.apache.logging.log4j.Logger;

import javax.servlet.*;
import javax.servlet.annotation.WebFilter;
import javax.servlet.http.HttpServletRequest;
import java.io.IOException;

@WebFilter(filterName = "LogBrowser",urlPatterns = "/*")
public class LogBrowserFilter implements Filter {

private static Logger logger = LogManager.getLogger(LogBrowser.class);

    public void destroy() {
    }

public void doFilter(ServletRequest req, ServletResponse resp, FilterChain chain) throws ServletException, IOException {

//Get userAgent that contain browse informations.
String userAgent = ((HttpServletRequest)req).getHeader("User-Agent");

//Get IP of Client that sent a resquest.
String ip = ((HttpServletRequest)req).getRemoteAddr();

//Logging the informations of IP and Browser.
logger.info("IP: "+ip +" Browser info: "+userAgent);

//Following to the next filter. If none next filter exist, follow to main logic.
chain.doFilter(req, resp);

}

public void init(FilterConfig config) throws ServletException {

    }

}

Popularity 1/10 Helpfulness 1/10 Language java

Source: Grepper

Tags: java

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Contributed on Feb 21 2023

Pragya Keshap

0 Answers Avg Quality 2/10

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