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size sort ts

Justin Burnel answered on April 5, 2023 Popularity 1/10 Helpfulness 3/10

answer size sort ts

size sort ts

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function sortSize(size: string []) {
  return size.sort((a: string, b: string) => {
    const order = ["xxs", "xs", "s", "m", "l", "xl", "xxl", "2xl", "3xl", "4xl", "5xl", "one size"];
    const aIndex = order.indexOf(a.toLowerCase());
    const bIndex = order.indexOf(b.toLowerCase());
    return aIndex - bIndex;
  });

}
// works with this one
let size: string[] = ['XL', 's', '1', '10', '2xl', '3', '0', 'xs', 'm', '3T', 'xxl', 'xxs', 'one size'];

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Contributed on Apr 05 2023

Justin Burnel

0 Answers Avg Quality 2/10

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