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anurag3301 answered on May 26, 2022 Popularity 10/10 Helpfulness 1/10

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import numpy as np

def qr_method(A, max_iterations=1000, tolerance=1e-6):
    n = A.shape[0]
    eigenvalues = np.zeros(n)

    for i in range(max_iterations):
        Q, R = np.linalg.qr(A)
        A = np.dot(R, Q)

        # Check if the matrix is already upper triangular
        if np.abs(np.sum(np.tril(A, -1))) < tolerance:
            break

    # Extract the eigenvalues from the diagonal of the upper triangular matrix
    for i in range(n):
        eigenvalues[i] = A[i, i]

    # Compute the eigenvectors using back substitution
    eigenvectors = []
    for eigenvalue in eigenvalues:
        B = A - eigenvalue * np.eye(n)
        eigenvector = np.zeros(n)
        eigenvector[-1] = 1

        for i in range(n-2, -1, -1):
            eigenvector[i] = np.dot(B

Popularity 10/10 Helpfulness 1/10 Language python

Source: chat.openai.com

Tags: python

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Contributed on Jun 26 2023

anurag3301

0 Answers Avg Quality 2/10

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<img src="data:image/png;base64, {{ base64_encode(QrCode::format('png')->size(100)->generate('Make me into an QrCode!')) }} ">

Popularity 10/10 Helpfulness 1/10 Language whatever

Source: stackoverflow.com

Tags: qr-code

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Contributed on Sep 13 2022

Ibrahim Aljammal

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<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js"></script>
<script src="https://rawgit.com/schmich/instascan-builds/master/instascan.min.js"></script>
<label id="label">Account ID </label>
<input type="text" name="accId" required="" class="idnum" style="width: 108px;margin-right: 15px;" value="">
<br/>
<label id="label">Customer Name </label>
<br/>
<input type="text" readonly="" name="name" class="idname" required="" value="">

Popularity 10/10 Helpfulness 1/10 Language html

Source: stackoverflow.com

Tags: html

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Contributed on May 26 2022

Annoying Alligator

0 Answers Avg Quality 2/10

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let scanner = new Instascan.Scanner({
  video: document.getElementById('preview'),
  mirror: false
});

Instascan.Camera.getCameras().then(function(cameras) {
  if (cameras.length > 0) {
    scanner.start(cameras[0]);
  } else {
    console.error('No cameras found.');
    alert('No cameras found.');
  }
}).catch(function(e) {
  console.error(e);
  alert(e);
});


$(function() {
  const re = /(\d+-\d+)\s+(.*)/;
  scanner.addListener('scan', function(content) {
    console.log(content);
    if (!re.test(content)) {
      console.log("malformed strings")
      return;
    }
    const [_, id, name] = content.match(re);
    $(".idnum").val(id);
    $(".idname").val(name.trim());
  });
})

Popularity 10/10 Helpfulness 1/10 Language javascript

Source: stackoverflow.com

Tags: javascript j

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Contributed on May 26 2022

Annoying Alligator

0 Answers Avg Quality 2/10

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