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most frequent number in a array using javascript

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Muhammad Al Amin Rifat answered on June 15, 2022 Popularity 7/10 Helpfulness 2/10

answer most frequent number in a array using javascript

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most frequent number in a array using javascript

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function findMostFrequentElement(inputArray) {
  if (inputArray.length === 0) {
    return null; // Return null for an empty array
  }

  const frequencyCount = {};
  let mostFrequentElement;
  let maxFrequency = 0;

  for (const num of inputArray) {
    frequencyCount[num] = (frequencyCount[num] || 0) + 1;

    if (frequencyCount[num] > maxFrequency) {
      maxFrequency = frequencyCount[num];
      mostFrequentElement = num;
    }
  }

  return mostFrequentElement;
}

// Test the program
const inputArray = [3, 5, 2, 5, 3, 3, 1, 4, 5];
const mostFrequent = findMostFrequentElement(inputArray);
console.log(mostFrequent); // Output: 3

Popularity 7/10 Helpfulness 2/10 Language javascript

Source: chat.openai.com

Tags: javascript using

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Contributed on Jul 26 2023

Muhammad Al Amin Rifat

0 Answers Avg Quality 2/10

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get most frequent element in array javascript

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get most frequent element in array javascript

var mostFrequentEven = function(nums) {
    newMap = new Map();
    
    const frequency = nums => { 
        
        nums.forEach((item) => {
            if(newMap.has(item)) newMap.set(item, newMap.get(item) + 1)
            else newMap.set(item, 1)
        })
        
        const sortedArr = Array.from(newMap.keys()).sort((a, b) => {
            if (newMap.get(a) !== newMap.get(b)) {
                return newMap.get(b) - newMap.get(a);
            } else {
                return a - b;
            }
        });
    
    return sortedArr.length !== 0 ? sortedArr[0] : -1
    
    }

    return frequency(nums)
};

Popularity 8/10 Helpfulness 3/10 Language javascript

Source: Grepper

Tags: javascript get element j

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Contributed on Mar 10 2023

ayaan

0 Answers Avg Quality 2/10

javascript most frequent in a list

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function findMostFrequent(arr) {
	var repsCount = {};
	for (i = 0; i < arr.length; i++) {
		if (!repsCount[arr[i]]) {
			repsCount[arr[i]] = 1;
		} else {
			repsCount[arr[i]] = repsCount[arr[i]] + 1;
		}
	}
	var occursMore = [];
	for (var key in repsCount) {
		if (repsCount[key] > occursMore) {
			occursMore.push(key);
		}
	}
	return occursMore;
}

Popularity 9/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript list

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Contributed on Jun 15 2022

Fierce Ferret

0 Answers Avg Quality 2/10

most frequent number in a array using javascript

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