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python async return values

Luke Harwood answered on August 17, 2023 Popularity 6/10 Helpfulness 1/10

answer python async return values

python async return values

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#!/usr/bin/env python3
import asyncio

@asyncio.coroutine
def func_normal():
    print('A')
    yield from asyncio.sleep(5)
    print('B')
    return 'saad'

@asyncio.coroutine
def func_infinite():
    for i in range(10):
        print("--%d" % i)
    return 'saad2'

loop = asyncio.get_event_loop()
tasks = func_normal(), func_infinite()
a, b = loop.run_until_complete(asyncio.gather(*tasks))
print("func_normal()={a}, func_infinite()={b}".format(**vars()))
loop.close()

Popularity 6/10 Helpfulness 1/10 Language python

Source: stackoverflow.com

Tags: python

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