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rust auth

Prithu Mainali answered on August 26, 2023 Popularity 5/10 Helpfulness 2/10

answer rust auth

rust auth

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use reqwest::Client;
use socks::Socks4Stream;
use tokio::fs::File;
use tokio::io::{AsyncBufReadExt, BufReader};
use tokio::net::TcpStream;
use tokio::runtime;

#[tokio::main]
async fn main() -> Result<(), Box<dyn std::error::Error>> {
    // Read the proxy addresses from a file
    let proxy_file_path = "proxy_list.txt"; // Path to your proxy list file
    let proxy_addresses = read_proxy_addresses(proxy_file_path).await?;

    // Setup the reqwest client
    let client = Client::builder()
        .use_rustls_tls() // If you want to use TLS
        .build()?;

    // Prepare the request URLs
    let target_urls = vec![
        "http://www.example.com", // Add your desired URLs here
        "http://www.another-example.com",
    ];

    for url in target_urls {
        for proxy_addr in &proxy_addresses {
            match send_request_through_socks4_proxy(&client, url, proxy_addr).await {
                Ok(_) => {
                    println!("Request successful through proxy: {}", proxy_addr);
                    break; // Move to the next URL after a successful request
                }
                Err(err) => {
                    eprintln!("Error with proxy {}: {}", proxy_addr, err);
                }
            }
        }
    }

    Ok(())
}

async fn read_proxy_addresses(file_path: &str) -> Result<Vec<String>, Box<dyn std::error::Error>> {
    let file = File::open(file_path).await?;
    let reader = BufReader::new(file);
    let mut proxy_addresses = Vec::new();

    for line in reader.lines() {
        let line = line?;
        proxy_addresses.push(line);
    }

    Ok(proxy_addresses)
}

async fn send_request_through_socks4_proxy(
    client: &Client,
    url: &str,
    proxy_addr: &str,
) -> Result<(), Box<dyn std::error::Error>> {
    let proxy_stream = TcpStream::connect(proxy_addr).await?;
    let socks_proxy = Socks4Stream::connect(proxy_stream, url).await?;

    let response = client.get(url).send().await?;
    println!("Response: {:?}", response);

    Ok(())
}

Popularity 5/10 Helpfulness 2/10 Language rust

Source: chat.openai.com

Tags: rust

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Contributed on Aug 26 2023

Prithu Mainali

0 Answers Avg Quality 2/10

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