This Python code demonstrates the implementation of a singly linked list and how to insert a node at the front of the linked list

Aishwarya M answered on August 30, 2023 Popularity 1/10 Helpfulness 1/10

answer This Python code demonstrates the implementation of a singly linked list and how to insert a node at the front of the linked list

This Python code demonstrates the implementation of a singly linked list and how to insert a node at the front of the linked list

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# node structure
class Node:
  def __init__(self, data):
    self.data = data
    self.next = None

#class Linked List
class LinkedList:
  def __init__(self):
    self.head = None

  #Add new element at the start of the list
  def push_front(self, newElement):
    newNode = Node(newElement)
    newNode.next = self.head 
    self.head = newNode   

  #display the content of the list
  def PrintList(self):
    temp = self.head
    if(temp != None):
      print("The list contains:", end=" ")
      while (temp != None):
        print(temp.data, end=" ")
        temp = temp.next
      print()
    else:
      print("The list is empty.")

# test the code                  
MyList = LinkedList()

#Add three elements at the start of the list.
MyList.push_front(10)
MyList.push_front(20)
MyList.push_front(30)
MyList.PrintList()

Popularity 1/10 Helpfulness 1/10 Language python

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Tags: implementation insert linked-list python this

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Contributed on Aug 30 2023

Aishwarya M

0 Answers Avg Quality 2/10

This Python code demonstrates the implementation of a singly linked list and how to insert a node at the front of the linked list

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