JS array.push() temporarily pushing

Smole PP answered on December 28, 2023 Popularity 1/10 Helpfulness 1/10

answer JS array.push() temporarily pushing

JS array.push() temporarily pushing

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// Answer for Node.js, cheerio
// Assuming you are using .each(async (i, el) => {...})
// The thing with .each() is that it fucks up with async functions.

// Incorrect:
$("x").children().each(async (i, el) => {
  el = $(el);
  // a lot of processing...
});

// Correct:
// Note: Make sure you are in async function:
const X_children = Array.from($("x").children());

for (let X_child of X_children) {
  X_child = $(X_child);
  // a lot of processing.
};

// Avoid using for (let i = 0; ..) loop since it doesn't care about async.

Popularity 1/10 Helpfulness 1/10 Language javascript

Source: Grepper

Tags: javascript

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Contributed on Dec 28 2023

Smole PP

0 Answers Avg Quality 2/10

JS array.push() temporarily pushing

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