Breaking News: Grepper is joining You.com. Read the official announcement!

binary tree level order traversal

Add Answer

Zealous Zebra answered on January 16, 2022 Popularity 9/10 Helpfulness 1/10

answer binary tree level order traversal

related binary tree level traversal

related level order traversal of tree cpp

related level order traversal of tree c

related level order traversal of binary tree c++

binary tree level order traversal

Comment

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public List<List<Integer>> levelOrder(TreeNode root) {
        List<List<Integer>> list = new ArrayList<>();
        Deque<TreeNode> queue = new ArrayDeque<>();
        if(root==null)
            return list;
        queue.offerLast(root);
        while(!queue.isEmpty())
        {
            ArrayList<Integer> l= new ArrayList<>();
            int size=queue.size();
            for(int i=0;i<size;i++)
            {
                TreeNode node=queue.pollFirst();
                if(node.left!=null)
                    queue.offerLast(node.left);
                if(node.right!=null)
                    queue.offerLast(node.right);
                l.add(node.val);

            }
            list.add(l);

        }

        return list;
        
        
    }
}

Popularity 9/10 Helpfulness 1/10 Language java

Source: Grepper

Tags: binary-tree java traversal

Link to this answer
Share Copy Link

Contributed on Jun 22 2023

Zealous Zebra

0 Answers Avg Quality 2/10

Closely Related Answers

binary tree level traversal

Comment

    public static void levelOrderTraversal(Node root)
    {
        // base case
        if (root == null) {
            return;
        }
 
        // create an empty queue and enqueue the root node
        Queue<Node> queue = new ArrayDeque<>();
        queue.add(root);
 
        // to store the current node
        Node curr;
 
        // loop till queue is empty
        while (!queue.isEmpty())
        {
            // process each node in the queue and enqueue their
            // non-empty left and right child
            curr = queue.poll();
 
            System.out.print(curr.key + " ");
 
            if (curr.left != null) {
                queue.add(curr.left);
            }
 
            if (curr.right != null) {
                queue.add(curr.right);
            }
        }
    }

Popularity 10/10 Helpfulness 2/10 Language java

Source: www.techiedelight.com

Tags: binary-tree bina

Link to this answer
Share Copy Link

Contributed on Jan 16 2022

PrashantUnity

0 Answers Avg Quality 2/10

level order traversal of tree cpp

Comment

// Recursive CPP program for level
// order traversal of Binary Tree
#include <bits/stdc++.h>
using namespace std;
 
/* A binary tree node has data,
pointer to left child
and a pointer to right child */
class node {
public:
    int data;
    node *left, *right;
};
 
/* Function prototypes */
void printCurrentLevel(node* root, int level);
int height(node* node);
node* newNode(int data);
 
/* Function to print level
order traversal a tree*/
void printLevelOrder(node* root)
{
    int h = height(root);
    int i;
    for (i = 1; i <= h; i++)
        printCurrentLevel(root, i);
}
 
/* Print nodes at a current level */
void printCurrentLevel(node* root, int level)
{
    if (root == NULL)
        return;
    if (level == 1)
        cout << root->data << " ";
    else if (level > 1) {
        printCurrentLevel(root->left, level - 1);
        printCurrentLevel(root->right, level - 1);
    }
}
 
/* Compute the "height" of a tree -- the number of
    nodes along the longest path from the root node
    down to the farthest leaf node.*/
int height(node* node)
{
    if (node == NULL)
        return 0;
    else {
        /* compute the height of each subtree */
        int lheight = height(node->left);
        int rheight = height(node->right);
 
        /* use the larger one */
        if (lheight > rheight) {
            return (lheight + 1);
        }
        else {
            return (rheight + 1);
        }
    }
}
 
/* Helper function that allocates
a new node with the given data and
NULL left and right pointers. */
node* newNode(int data)
{
    node* Node = new node();
    Node->data = data;
    Node->left = NULL;
    Node->right = NULL;
 
    return (Node);
}
 
/* Driver code*/
int main()
{
    node* root = newNode(1);
    root->left = newNode(2);
    root->right = newNode(3);
    root->left->left = newNode(4);
    root->left->right = newNode(5);
 
    cout << "Level Order traversal of binary tree is \n";
    printLevelOrder(root);
 
    return 0;
}
 
// This code is contributed by rathbhupendra

Popularity 9/10 Helpfulness 1/10 Language cpp

Source: www.geeksforgeeks.org

Tags: c++

Link to this answer
Share Copy Link

Contributed on Sep 02 2022

whoibrar

0 Answers Avg Quality 2/10

level order traversal of tree c

Comment

// Recursive C program for level
// order traversal of Binary Tree
#include <stdio.h>
#include <stdlib.h>
 
/* A binary tree node has data,
   pointer to left child
   and a pointer to right child */
struct node {
    int data;
    struct node *left, *right;
};
 
/* Function prototypes */
void printCurrentLevel(struct node* root, int level);
int height(struct node* node);
struct node* newNode(int data);
 
/* Function to print level order traversal a tree*/
void printLevelOrder(struct node* root)
{
    int h = height(root);
    int i;
    for (i = 1; i <= h; i++)
        printCurrentLevel(root, i);
}
 
/* Print nodes at a current level */
void printCurrentLevel(struct node* root, int level)
{
    if (root == NULL)
        return;
    if (level == 1)
        printf("%d ", root->data);
    else if (level > 1) {
        printCurrentLevel(root->left, level - 1);
        printCurrentLevel(root->right, level - 1);
    }
}
 
/* Compute the "height" of a tree -- the number of
    nodes along the longest path from the root node
    down to the farthest leaf node.*/
int height(struct node* node)
{
    if (node == NULL)
        return 0;
    else {
        /* compute the height of each subtree */
        int lheight = height(node->left);
        int rheight = height(node->right);
 
        /* use the larger one */
        if (lheight > rheight)
            return (lheight + 1);
        else
            return (rheight + 1);
    }
}
 
/* Helper function that allocates a new node with the
   given data and NULL left and right pointers. */
struct node* newNode(int data)
{
    struct node* node
        = (struct node*)malloc(sizeof(struct node));
    node->data = data;
    node->left = NULL;
    node->right = NULL;
 
    return (node);
}
 
/* Driver program to test above functions*/
int main()
{
    struct node* root = newNode(1);
    root->left = newNode(2);
    root->right = newNode(3);
    root->left->left = newNode(4);
    root->left->right = newNode(5);
 
    printf("Level Order traversal of binary tree is \n");
    printLevelOrder(root);
 
    return 0;
}

Popularity 9/10 Helpfulness 1/10 Language c

Source: www.geeksforgeeks.org

Tags: c traversal traversa

Link to this answer
Share Copy Link

Contributed on Sep 02 2022

whoibrar

0 Answers Avg Quality 2/10

level order traversal of binary tree c++

Comment

/*
node class contains:
node* left;
node* right;
int value;
*/
void levelOrder(node* root){
  node* ptr=nullptr;
  queue<node*> q;
  q.push(root);
  while(!q.empty()){
    ptr=q.front();
    cout<<ptr->value<<endl;
    if(ptr->left!=nullptr){
q.push(ptr->left);
  }
    if(ptr->right!=nullptr){
    q.push(ptr->right);
    }
    q.pop();
  }
}

Popularity 10/10 Helpfulness 1/10 Language cpp

Source: Grepper

Tags: binary-tree bina

Link to this answer
Share Copy Link

Contributed on May 01 2022

Shiny Spider

0 Answers Avg Quality 2/10

binary tree level order traversal

Contents

More Related Answers

binary tree level order traversal

Closely Related Answers

binary tree level traversal

level order traversal of tree cpp

level order traversal of tree c

level order traversal of binary tree c++

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.