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Search option for Javasript

manelisi madubela answered on October 17, 2023 Popularity 1/10 Helpfulness 1/10

answer Search option for Javasript

related Search option for Javasript

Search option for Javasript

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const person = { name: "John", age: 30, job: "Developer" };
const searchKey = "age";

if (searchKey in person) {
    console.log(`Found: ${searchKey}: ${person[searchKey]}`);
} else {
    console.log(`Key not found.`);
}

Popularity 1/10 Helpfulness 1/10 Language javascript

Source: chat.openai.com

Tags: javascript search

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Contributed on Oct 17 2023

manelisi madubela

0 Answers Avg Quality 2/10

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Search option for Javasript

Comment

const numbers = [1, 2, 3, 4, 5];
const searchNumber = 3;

if (numbers.includes(searchNumber)) {
    console.log(`${searchNumber} is in the array.`);
} else {
    console.log(`${searchNumber} is not in the array.`);
}

Popularity 1/10 Helpfulness 1/10 Language javascript

Source: chat.openai.com

Tags: javascript search

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Contributed on Oct 17 2023

manelisi madubela

0 Answers Avg Quality 2/10

Search option for Javasript

Comment

const text = "This is a sample text.";
const regex = /sample/;
const isFound = regex.test(text);

if (isFound) {
    console.log("Found");
} else {
    console.log("Not found");
}

Popularity 1/10 Helpfulness 1/10 Language javascript

Source: chat.openai.com

Tags: javascript search

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Contributed on Oct 17 2023

manelisi madubela

0 Answers Avg Quality 2/10

Search option for Javasript

Comment

const text = "This is a sample text.";
const searchTerm = "sample";
const foundIndex = text.indexOf(searchTerm);

if (foundIndex !== -1) {
    console.log(`Found at index: ${foundIndex}`);
} else {
    console.log("Not found");
}

Popularity 1/10 Helpfulness 1/10 Language javascript

Source: chat.openai.com

Tags: search javascript

Link to this answer
Share Copy Link

Contributed on Oct 17 2023

manelisi madubela

0 Answers Avg Quality 2/10

Search option for Javasript

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Search option for Javasript

Search option for Javasript

Search option for Javasript

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